√ax-√by=b-a and √bx-√ay=0 then x+y
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(x + y) = - (√a + √b) if √a x-√b y = b - a and √b x-√a y = 0
Step-by-step explanation:
√a x-√b y = b - a Eq1
√b x-√a y = 0 Eq2
Eq1 - Eq1
=> x(√a - √b) - y(√b - √a) = b - a
=> x(√a - √b) + y(√a - √b) = b - a
=> (x + y) (√a - √b) = b - a
=> (x + y) (√a - √b) = (√b + √a)(√b - √a)
=> (x + y) = - (√b + √a)
=> (x + y) = - (√a + √b)
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