......Ax+By+C=0 is A(x1.....
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Hi there,
The slope of the line Ax + By + C = 0 is
y = -(A/B)x + (-C/B)
Now,
We know that parallel lines have the same slope.
=>Slope of the other line=m= -(A/B)
Hence,
The required eqn. of the line is
(y - y1) = m (x - x1)
(y - y1) = -(A/B) (x - x1)
B(y - y1) = -A (x - x1)
Hence, A(x - x1) + B(y - y1) = 0.
#SB.
The slope of the line Ax + By + C = 0 is
y = -(A/B)x + (-C/B)
Now,
We know that parallel lines have the same slope.
=>Slope of the other line=m= -(A/B)
Hence,
The required eqn. of the line is
(y - y1) = m (x - x1)
(y - y1) = -(A/B) (x - x1)
B(y - y1) = -A (x - x1)
Hence, A(x - x1) + B(y - y1) = 0.
#SB.
soubhik:
Mark as brainliest,buddy
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