ax + by=c and mx+ny=d and an≠bm then these simultaneous equations have -
(A) Only one common solution.
(B) No solution
(C) Infinite number of solutions
(D) Only two solutions
The answer is (A)
please explain it
Answers
Answered by
214
Hi ,
********************************************
Relation between the coefficients and
nature of system of equations.
ax+ by - c = 0 , mx + ny - d = 0 are two
linear equations ,
if a/m ≠ b/n
or
an ≠ bm
then the pair of linear
equations is consistent.
The lines intersecting each other .
Therefore ,
they have one common point
and one Unique solution.
******************************************†
Option ( A ) is correct.
I hope this helps you.
: )
********************************************
Relation between the coefficients and
nature of system of equations.
ax+ by - c = 0 , mx + ny - d = 0 are two
linear equations ,
if a/m ≠ b/n
or
an ≠ bm
then the pair of linear
equations is consistent.
The lines intersecting each other .
Therefore ,
they have one common point
and one Unique solution.
******************************************†
Option ( A ) is correct.
I hope this helps you.
: )
Answered by
50
Relation between the coefficients and
nature of system of equations.
ax+ by - c = 0 , mx + ny - d = 0 are two
linear equations ,
if a/m ≠ b/n
or
an ≠ bm
then the pair of linear
equations is consistent.
The lines intersecting each other .
Therefore ,
they have one common point
and one Unique solution.
******************************************†
Option ( A ) is correct.
I hope this helps you..
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