Math, asked by satagr, 1 year ago

ax/cosA +by/sinA=(a²+b²); ax sinA/cos²A -by cosA/sin²A=0 pt : ax⅔+ by⅔=(a²-b²)⅔

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Answered by christien97

0

https://www.math10.com/en/geometry/trigonometry-and-geometry-conversions/trigonometry.html

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