Question

ax²+bx+c=0 के मूल



plz help​

Answer 1

Answer:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

Answer 2

Step-by-step explanation:

$x = - b \binom{ + }{ - } \sqrt{b {}^{2} - 4ac} \div 2a$