Question

ax2-y2+4x-y=0 represents a pair of line then a=

Answer 1

Answer:

$\boxed{Your\:Solution}$

Step-by-step explanation:

$ax^{2} -y^{2} +4x-y=0\:represent\:pair\:of\:straight\:lines\left[\begin{array}{ccc}a&0&2\\0&-1&-12\\2&-12&0\end{array}\right] =0$

=> $a(0-\frac{1}{4} )+2(0+2)=0$

$\frac{-a}{4} +4=0=>a=16$

$\boxed{Hope\:it\:Helps}$

Answer 2

Step-by-step explanation:

ax2−y2+4x−y=0

represents pair Straights

= ∣020−1−122−120∣=0

= a(0−14)+2(0+2)=0

= −a4+4=0

= a=16