Question

AXB is a semicircle AB is a diameter, AB = 12 AYB is a arc having measure 120 find the area of shaded rigion​

Answer 1

Answer:

Step-by-step explanation:

first find the area of semicircle

area of semicircle is π*radius square / 2

22/7*6*6/2 =56.571

therefore area of shaded region is 120-56.571= 63.429

Answer 2

The area of the shaded region is 18.84 square units

Explanation:

Given that AXB is a semicircle.

AB is the diameter of 12 units.

Radius $r=\frac{d}{2}$

              $=\frac{12}{2}$

              $=6$

Thus, radius is 6 units.

AYB is an arc having 120°

Area of the semicircle:

Area of the semicircle = $\frac{1}{2} \pi r^2$

                                     = $\frac{1}{2} (3.14) (6)^2$

                                     = $\frac{1}{2} (3.14)(36)$

                                     = $56.52 \ square \ units$

Thus, the area of the semicircle is 56.52 square units.

Area of the sector:

Area of the sector = $\frac{\theta \times \pi}{360} \times r^{2}$

                              = $\frac{120 \times 3.14}{360} \times(6)^{2}$

                              = $\frac{120 \times 3.14}{360} \times36$

                              = $37.68 \ square \ units$

Thus, the area of the sector is 37.68 square units.

Area of the shaded region:

Area of the shaded region = Area of the semicircle - Area of the sector

                                            = 56.52 - 37.68

                                            = 18.84 square units

Hence, the area of the shaded region is 18.84 square units

Learn more:

(1) ABCD is a quadrant of a circle of radius 28 cm And a semicircle BEC is drawn with BC as diameter find the area of the shaded region

brainly.in/question/2508965

(2) Find the area of sector, whose radius is 7 cm. with the given angle:

i. 60° ii. 30° iii. 72° iv. 90° v. 120°

brainly.in/question/7657742