axsq +(1+asq) x+a solve the problem and give me full solution
QGP:
Do we have to factorise this?
Answers
Answered by
0
Hi ,
ax² + ( 1 + a² )x + a
= ax² + x + a²x + a
= x( ax + 1 ) + a( ax + 1 )
= ( ax + 1 ) ( x + a )
I hope this helps you.
: )
ax² + ( 1 + a² )x + a
= ax² + x + a²x + a
= x( ax + 1 ) + a( ax + 1 )
= ( ax + 1 ) ( x + a )
I hope this helps you.
: )
Answered by
0
ax² + (1 +a²)x + a
ax² + x + a²x + a
x(ax + 1) + a(ax + 1)
( x + a) (ax + 1)
I hope this will help you
(-:
ax² + x + a²x + a
x(ax + 1) + a(ax + 1)
( x + a) (ax + 1)
I hope this will help you
(-:
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