.AXYZ is a right triangle with ZY = 90° XY = 3 cm; YZ = 4 cm and XZ = 5 cm. Find the
area of the triangle. Also find the distance between Y and XZ.
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Area =(1/2)×base×height
Let us take base as YZ=4 cm then the height is XY=3 cm
Area=(1/2)×(4cm)×(3cm)
Area=6cmsquare
When we take base as XZ=5cm then the height will become the distance between Y and XZ.
6cm=(1/2)×(5cm)×(distance between Y and XZ)
THEREFORE distance between Y and XZ is 12/5
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