Question

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[2]
A student standing at the end of a closed corridor 86 m long
blows a short blast on a whistle and notes a series of echoes. If
the time from the blast to the fifth echo is 2.5 s, calculate the
speed of sound.

Answer 1

Explanation:

• Distance = 86 m
• Time taken to hear the 5th echo = 2.5 s

Therefore,

Time taken to hear the first echo is = 2.5/5 = 0.5 s

Since,

we know that,

$speed = \frac{distnce}{time}$

We also know that ,

In case of echo distance travelled by the sound = 2* distance = 86*2 = 172 m

Therefore,

Speed = 172/0.5 = 344 m/s

So, the speed of sound is 344 m/sec.

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Answer 2

Thus the speed of sound is 344 m/s.

Explanation:

Given data:

• Distance = 86 m
• Time taken to hear the 5th echo = 2.5 s
• Time taken to hear the first echo is = 2.5/5 = 0.5 s

We know that:

Speed = distance / time

We also know that:

In case of echo distance travelled by the sound = 2 x distance

Echo distance travelled by the sound= 86 x 2 = 172 m

Therefore,

Speed = 172/0.5 = 344 m/s

Thus the speed of sound is 344 m/s.