aye!!
answer this please ^^
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Hey !!!
cos(3x - 5 ) ²
Using chain rule
=> 1st of all defferentiate 3x - 5
dy/dx = 3x - 5
dy/dx = d(3x - 5)/dx
dy/dx = 3 ----1)
after that differentiate
(3x - 5) ²
dy/dx = d(3x - 5)² /dx
dy/dx = 2(3x - 5) -----2)
lastly differentiate
cos ( 3x - 5) ²
dy/dx = dcos(3x - 5)²/dx
dy/dx = - sin(3x - 5)²
d/dx = -sin(3x -5)²
from equation 1st and 2nd and 3rd
.
= 3 × 2( 3x - 5) -sin(3x - 5)²
Answer = -6sin(3x-5) (3x - 5)²
___________________________
Hope it helps you !!!
@Rajukumar111
cos(3x - 5 ) ²
Using chain rule
=> 1st of all defferentiate 3x - 5
dy/dx = 3x - 5
dy/dx = d(3x - 5)/dx
dy/dx = 3 ----1)
after that differentiate
(3x - 5) ²
dy/dx = d(3x - 5)² /dx
dy/dx = 2(3x - 5) -----2)
lastly differentiate
cos ( 3x - 5) ²
dy/dx = dcos(3x - 5)²/dx
dy/dx = - sin(3x - 5)²
d/dx = -sin(3x -5)²
from equation 1st and 2nd and 3rd
.
= 3 × 2( 3x - 5) -sin(3x - 5)²
Answer = -6sin(3x-5) (3x - 5)²
___________________________
Hope it helps you !!!
@Rajukumar111
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