Math, asked by anjalisingh121, 10 months ago

Ayisha's age is 1/6th of her father's age. Ayisha's father's age will be twice Shankar's age after
10
years. If Shankar's eight birthdays was celebrated two years before, then what is Ayisha's present age.

Answers

Answered by Pitymys
2

Answer:

5  years

Step-by-step explanation:

Let Ayisha's present age  =  x

Then, her father's age  = 6x

Given that Ayisha's father's age will be twice Shankar's age after  10 year

Therefore, Shankar's age after  10  years  = 1/2  x ( 6 x + 10 ) = 3 x + 5

Also given that Shankar's eight birthdays was celebrated two years before.

Therefore, Shankar's age after  10  years  = 8 + 12 = 20

3 x  + 5 = 20

⇒ x = 15 /3 = 5

Therefore, Ayisha's present age  = 5  years

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