Math, asked by Parvani4388, 1 year ago

Ayisha's age is 1/6th of her father's age. ayisha 's father's age will be twice the age of shankar's age after 10 years. if shankar's eight birthdays was celebrated two years before, then what is ayisha 's present age.
a. 10 years
b. 5 years
c. 8 years
d. 12 years

Answers

Answered by vishi131
3
Since Shankar's birthday is on 29 February which comes in leap year so it can be 10 years
Answered by pinquancaro
3

Answer:

Option b - 5 years                                  

Step-by-step explanation:

Given : Ayisha's age is 1/6th of her father's age. ayisha 's father's age will be twice the age of Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before.

To find : What is Ayisha 's present age?

Solution :

If Shankar's eight birthdays was celebrated two years before.

So, The present age of Shankar's is 10 years.

After 10 years,

Shankar's age became 20 years.

Ayisha 's father's age will be twice the age of Shankar's age after 10 years.

i.e. Ayeasha's father age is 2(20)=40 years.

Present age of Ayesha's father is 40-10=30 years.

According to question,

Ayisha's age is 1/6th of her father's age.

i.e. \frac{1}{6}\times 30=5

Ayesha's present age is 5 years.

Therefore, Option b is correct.

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