Math, asked by gauravkandoi3296, 16 days ago

Ayo is 37years and Abdulsalami is 6years old .how many years ago waseheir product of their age 96

Answers

Answered by devanandsahu800
0

Step-by-step explanation:

We want to know how many years need to be added to each person's age before the man will be twice as old as the sum of his two sons.

As each year passes, each person’s age will increase as one. So after one year, the man will be 37+1 years old, the older son will be 8+1, and the younger son will be 3+1. After two years, the “+ 1”s all become “+2”, and so on for each year.

We can substitute a letter for the year to make it general. Let’s use “y”.

So after “y” years, the man will be 37 + y, and the sons 8 + y and 3 + y. We want to know the value of y when the man’s age is twice the sum of the sons' ages.

In math (or algebra) we would write the equation:

37 + y = 2(8 + y + 3 + y)

Distribute the 2(…) across the additions inside:

37 + y = 16 + 2y + 6 + 2y

Combine:

37 + y = 22 + 4y

Isolate y on one side and the constants on the other:

y - 4y = 22 - 37

Simplify:

-3y = -15

Divide both sides by -3 to get a single y on one side:

y = 5

And there’s your answer: 5 years

It’s a good idea to verify, in case you make a mistake somewhere:

In 5 years, the man will be 42, and the sons 13 and 8. 13 + 8 is 21, which is half of 42. That satisfies the condition, so we’re good.

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