Question

Ayrton senna had to cover a distance of 60km .How ever he start 6 minuts

Answer 1

Answer:

Given

Distance ( d ) = 60 km

Time ( t ) = 6 min

1 min = 60 sec

6 min = 60 × 6 = 360 sec

Speed ( s ) = ?

Speed = d /t

speed = 60 / 360

speed = 6 m/sec

Answer 2

$v=24\ km.hr^{-1}$

Assuming that he started 6 minutes later than his scheduled time and raced at a speed 1 km/h higher than his originally planned speed and reached the finish at the time he would reach it if he began to race strictly at the appointed time and raced with the assumed speed. Find the speed at which he traveled during the journey described.]

Explanation:

Given:

• Distance to be covered, $d=60\ km$

• Let the planned speed be v kilometers per hour.

• Then actual speed of running will be (v+1) kilometers per hour.

We know,

$\rm time=\frac{distance}{speed}$

Time taken in both the cases is equal according to the question:

$t_1=t_2$

$\Rightarrow \frac{d}{v} =\frac{d}{(v+1)} +\frac{6}{60}$

$\frac{60}{v} =\frac{60}{(v+1)} +\frac{6}{60}$

$v=24\ km.hr^{-1}$

#LearnMore

https://brainly.com/question/5176148