Question

Ays BC 3 reift for 6 ya exc fex
LABD - ZACD​

Answer 1

Explanation:

ANSWER

Given r

1

=3;r

2

=4;r

3

=6

Using the identity

r

1

=

r

1

1

+

r

2

1

+

r

3

1

=

3

1

+

4

1

+

6

1

=

24

8+6+4

=

24

18

=

4

3

∴

r

1

=

4

3

Hence r=

3

4

Answer 2

Answer:

Given r

1

=3;r

2

=4;r

3

=6

Using the identity

r

1

=

r

1

1

+

r

2

1

+

r

3

1

=

3

1

+

4

1

+

6

1

=

24

8+6+4

=

24

18

=

43

∴r1=43

Hence r=34