Math, asked by sangitasubbarai352, 3 months ago

Ayush bought a bicycle for Rs 6250 and had to sell it for Rs 5875 find his loss and loss per cent​

Answers

Answered by Anonymous
191

Question :

  • Ayush bought a bicycle for Rs 6250 and had to sell it for Rs 5875 find his loss and loss per cent.

Given :

  • Cost of bicycle = ₹6250

  • Selling price of bicycle = ₹5875

To Find :

  • His loss and loss percent.

Solution :

Its given that,

Cost of bicycle = ₹6250

Selling price of bicycle = ₹5875

To find loss :

 \large \sf { C.P-S.P }

 \large \sf  { =₹6250-₹5875 }

\large{\underline{\underline{\mathrm{Loss\:=₹375}}}}

To find loss percentage :

\large \sf Loss\% =  \frac{loss}{CP}  \times 100

 \large\sf =  \frac{375}{6250}  \times 100

 \large{\underline{\boxed{\mathfrak\pink{Loss\:=6\:percent}}}}

{\underline\mathbf{\; ∴Hence,\:the\:loss\:percent\:is\:6\:percent}}

Answered by MasterDhruva
11

Given :-

Cost price of a bicycle :- ₹6250

Selling price of a bicycle :- ₹5875

\:

To Find :-

The loss and the loss percentage of bicycle.

\:

How to do :-

Here, we are given with the cost price and the selling price of a bicycle. We are asked to find the loss rupees and the loss percentage of that bicycle. So,we can observe that the cost price is greater than selling price. When the cost price is greater, we'll always obtain with loss. So, first we should find the loss rupees by subtracting the cost price and the selling price. Later, the loss percentage can be found by using the given formula while solving.

\:

Solution :-

Loss rupees :-

 \tt \leadsto \underline{\boxed{\tt CP - SP}}

Substitute the given values.

{\tt \leadsto 6250 - 5875}

Subtract to get the value of loss.

{\tt \leadsto \pink{\underline{\boxed{\tt Rs \: \: 375}}}}

\:

Now, find the loss percentage by using the given formula below.

Loss percentage :-

{\tt \leadsto \underline{\boxed{\tt \dfrac{Loss}{Cost \: price} \times 100}}}

Substitute the given values.

{\tt \leadsto \dfrac{375}{6250} \times 100}

Write the denominator and the whole number given in lowest form by cancellation method.

{\tt \leadsto \dfrac{375}{\cancel{6250}} \times \cancel{100} = \dfrac{375}{125} \times 2}

Write the given fraction in lowest form by cancellation method.

{\tt \leadsto \cancel \dfrac{375}{125} \times 2 = \dfrac{3}{1} \times 2}

Multiply the remaining numbers to get the answer.

{\tt \leadsto \dfrac{3 \times 2}{1} = \pink{\underline{\boxed{\tt 6 \bf\%}}}}

\Huge\therefore The loss rupees is 375 and the loss percentage is 6%.

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\dashrightarrow Some related formulas :-

\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\  \bigstar \:  \sf{Gain = S.P - C.P} \\  \\ \bigstar \:  \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\  \\ \bigstar \:  \sf{S.P = \dfrac{100+Gain\%}{100} \times C.P} \\  \\ \bigstar \:  \sf{C.P =\dfrac{100}{100+Gain\%} \times S.P}  \\  \\\bigstar \:  \sf{S.P =  \dfrac{100-loss\%}{100} \times C.P}  \\  \\ \bigstar \:  \sf{C.P =\dfrac{100}{100-loss\%} \times S.P}\end{array}}

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