Ayushree bought two watches for ₹ 3605. She sold one at a profit of 15% and the other at a loss of 9%. If she obtained the same amount for each watch, find the cost price of each watch.
Answers
Answer:
Cost price of one watch is = Rs 1592.50
Cost price of second watch is Rs 2012.50
Step-by-step explanation:
Given, cost price of 2 watches is = Rs 3605. Let cost price of 1 watch be = Rs x .
Then ,CP of other watch will be = Rs 3605 – x.
We know that one is a gain and other is a loss.
Selling price of first watch (gain) = x + x×15/100
= x + x×3/20
= (20x+3x)/20
= Rs 23x/20
Selling price of second watch (loss)
= (3605 – x) × 91/100
= Rs (3605×91 – 91x)/100
So now, by equating both we get,
23x/20 = (3605×91 – 91x)/100
23x = (3605×91 – 91x)/5
23x × 5 = 3605×91 – 91x
115x + 91x = 3605×91
206x = 3605×91
x = (3605×91)/206
= 1592.50
∴ Cost price of one watch (x) is = Rs 1592.50
Cost price of second watch (3605 – x) is
(3605 – x) is = 3605 – 1592.50 = Rs 2012.50
Answer:
Step-by-step explanation:
sp1 =cp1(1+g%)
=cp1(1+15%) =1.15cp1
sp2 =cp2(1-l%)
=cp2(1-9%)
=0.91cp2
sp1=sp2
1.15cp1 = 0.91cp2
cp1/cp2 = 0.91/1.15 =91/115
cp1 =91x
cp2=115x
cp1+cp2=3605
91x+115x=3605
206x = 3605
x=17.5
cp1=1592.5
cp2=2012.5
hope this helps