Azhar has a mixture of hydrogen and oxygen gases in the ratio 1 is to 5 the ratio of mean kinetic energy of
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Hey dear,
● Answer- 1:1
● Explaination-
Average kinetic energy of a gas is independent of no of moles.
For hydrogen,
KEavg(H2) = 1/2 m × (vrms)^2
KEavg(H2) = 1/2 m × 5RT/m
KEavg(H2) = 5/2 RT
For oxygen,
KEavg(O2) = 1/2 M × (v'rms)^2
KEavg(O2) = 1/2 M × 5RT/M
KEavg(O2) = 5/2 RT
Ratio of KEavg(H2) to KEavg(O2) is-
KEavg(H2) / KEavg(O2) = (5/2 RT) / (5/2 RT)
KEavg(H2) / KEavg(O2) = 1
Hope this is useful...
● Answer- 1:1
● Explaination-
Average kinetic energy of a gas is independent of no of moles.
For hydrogen,
KEavg(H2) = 1/2 m × (vrms)^2
KEavg(H2) = 1/2 m × 5RT/m
KEavg(H2) = 5/2 RT
For oxygen,
KEavg(O2) = 1/2 M × (v'rms)^2
KEavg(O2) = 1/2 M × 5RT/M
KEavg(O2) = 5/2 RT
Ratio of KEavg(H2) to KEavg(O2) is-
KEavg(H2) / KEavg(O2) = (5/2 RT) / (5/2 RT)
KEavg(H2) / KEavg(O2) = 1
Hope this is useful...
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