Question

azimuthal angle is kept 45 and two projectiles are simultaneously projected with velocities 250m/s at inclinations 30 and 60.After what time they collide.​

Answer 1

Heya Mate

Here is your answer

h=(u^2)sin(2theta) / g , where theta is the angle with which the projectile was projected with the horizontal.

This formula states that the maximum height reached by the projectile is directly proportional to the sine of double angle.

So, the ratio will be sin(60)/sin(120)= 1

Also, as these angles are complementary, i.e. 60+30 = 90 degrees

The maximum height reached by these projectiles will be same.

Hope it helps