Math, asked by ambikapatil2007, 11 months ago

azlan's age is two times his sons age ten years ago he was four times his sons age.find their present ages

Answers

Answered by ardrashaji
3

Answer:

hope it help u

Step-by-step explanation:

let aslan son's present age be ' x '

azlan's present age =2x

ten year ago ,

azlan's son's age = x-10

azlan's age = 4(x-10)

4x - 40 + 10 = 2x ( adding 10 to their age gives their present age )

x = 15

azlan's age = 30

azlan's son's age = 15

Answered by Sauron
5

Answer:

The present age of Azlan's Son is 15 years

The present age of Azlan is 30 years

Step-by-step explanation:

Let,

The present age of Azlan's Son = x

The present age of Azlan = 2x

10 years ago,

The age of Azlan's Son = x - 10

The age of Azlan = 2x - 10

Also,

Azlan was four times his Son's age

So,

⇒ 4 (x - 10) = 2x - 10

⇒ 4x - 40 = 2x - 10

⇒ 4x - 2x = - 10 + 40

⇒ 2x = 30

⇒ x = 30 / 2

x = 15

____________________________

Value of 2x:

⇒ 2 (15)

⇒ 2 × 15

30

Therefore,

The present age of Azlan's Son is 15 years

The present age of Azlan is 30 years

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