Math, asked by ambikapatil2007, 9 months ago

azlan's age is two times his sons age ten years ago he was four times his sons age.find their present ages

Answers

Answered by ardrashaji
3

Answer:

hope it help u

Step-by-step explanation:

let aslan son's present age be ' x '

azlan's present age =2x

ten year ago ,

azlan's son's age = x-10

azlan's age = 4(x-10)

4x - 40 + 10 = 2x ( adding 10 to their age gives their present age )

x = 15

azlan's age = 30

azlan's son's age = 15

Answered by Sauron
5

Answer:

The present age of Azlan's Son is 15 years

The present age of Azlan is 30 years

Step-by-step explanation:

Let,

The present age of Azlan's Son = x

The present age of Azlan = 2x

10 years ago,

The age of Azlan's Son = x - 10

The age of Azlan = 2x - 10

Also,

Azlan was four times his Son's age

So,

⇒ 4 (x - 10) = 2x - 10

⇒ 4x - 40 = 2x - 10

⇒ 4x - 2x = - 10 + 40

⇒ 2x = 30

⇒ x = 30 / 2

x = 15

____________________________

Value of 2x:

⇒ 2 (15)

⇒ 2 × 15

30

Therefore,

The present age of Azlan's Son is 15 years

The present age of Azlan is 30 years

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