Question

(b) 0
(c) - 1
14. (1 + tano) (1 - sin 0) (1 + sin 0) (1 + cos 0) (1 - cos 0) (1 + coto) is equal to
(2) - 2
(b) 0
(c) 1​

Answer 1

Answer:

Step-by-step explanation:

(1 + tan0)(1 - sin0)(1 + sin0)(1 + cos0)(1 - cos0)(1 + cot0)

= (1 + tan0)(1 - sin^2(0))(1 - cos^2(0))(1 + cot0)

= (1 + 0)(1 - 0)(1 - 1)(1 + cot0)

= (1)(1)(0)(1+cot0)

= 0

(1 + tan0)(1 - sin0)(1 + sin0)(1 + cos0)(1 - cos0)(1 + cot0) = 0