Question

(b+1) and (b-1) are the sides of a right triangle then other side is​

Answer 1

Step-by-step explanation:

The other side of the traingle =

\begin{gathered} = \sqrt{(b + 1)(b - 1)} \\ = \sqrt{ {b}^{2} - {1}^{2} } \\ = \sqrt{ {b}^{2} - 1 } \end{gathered}

=

(b+1)(b−1)

=

b

2

−1

2

=

b

2

−1

hope it helps you

Answer 2

Answer:

The correct answer of this question is $x = \sqrt{2b^{2}+2 }$

Step-by-step explanation:

Given - (b+1) and (b-1) are the sides of a right triangle.

To Find - Write the other side of right triangle.

The hypotenuse square is equal to the base square plus the perpendicular square, according to Pythagoras' theorem.

Now, $x = \sqrt{(b+1)^{2}+(b-1)^{2} }$

$x = \sqrt{b^{2} + 2b+2 +b^{2} -2b+1 }$

$x = \sqrt{2b^{2} + 2b - 2b + 1 +1}$

now cancel +2b and -2b and we get,

$x = \sqrt{2b^{2} + 1 +1 }$

$x = \sqrt{2b^{2} +2}$

The other sides of a right triangle are $x = \sqrt{2b^{2}+2 }$

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