Question

[b+1] and [b-1] are the sides of a right triangle then other side is


plz don't snap​

Answer 1

${ab}^{2} + {bc}^{2} = {ca}^{2}$

$let \: {ca}^{2} \: be \: {x}^{2}. \\ {(b + 1)}^{2} + {(b - 1)}^{2} = {x}^{2}$

${b}^{2} + 2b \: + 1 \: + {b}^{2} \: - 2b \: + 1 = {x}^{2}$

$2 {b}^{2} + 2 \: = {x}^{2}$

$2( {b}^{2} + 1) = {x}^{2}$

so,

$x = \sqrt{2( {b}^{2} + 1) }$

$x = \sqrt{2} \sqrt{ {b}^{2} + 1}$

please mark me as brainliest!!!

Answer 2

Answer:

answer is 2^b

hope it helps you