Question

(b+1) and (b-1) are the sides of a right triangle then other side is​

Answer 1

Answer:

1. x=√b+1 is the answer by Pythagoras theorem in maths hypotenuse square us equal to base square plus perpendicular square

Answer 2

The other sides of a right triangle are $x=\sqrt{2b^{2}+2 }$.

Step-by-step explanation:

Given:

The sides of a right triangle are $(b+1)$ and $(b-1)$.

To find:

Find the other side of a right triangle.

Formula used: Pythagoras theorem.

Solution:

We know that Pythagoras' theorem states that the hypotenuse square is equal to the base square plus the perpendicular square.

So, $x=\sqrt{(b+1)^{2} + (b-1) ^{2} }$

$x=\sqrt{b^{2}+2b+2+b^{2}-2b+1 }$

$x=\sqrt{2b^{2}+2b-2b+1+1 }$

now cancel $+2b$ and $-2b$

we get, $x=\sqrt{2b^{2}+1+1 }$

$x=\sqrt{2b^{2}+2 }$

Hence, A right triangle's other sides are$x=\sqrt{2b^{2}+2 }$.

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