Question

(b) (1+tan? e) sin 0. cos 0 = tan o​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$sol {}^{n}$

LHS

$= (1 + tan {}^{2} o)sino.coso$

$= sec {}^{2} sino.coso$

$= \frac{1}{cos {}^{2}o } \times sino.coso$

$= \frac{1}{coso} \times sino$

$= \frac{sino}{coso}$

$= tano$

=RHS