Question

(b) 10% cows of a villager died in 2011.12 %2% of the
remaining cows dies in 2012. If the left out cows
are 63, how many cows did the villager have
originally?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

10% of cows= 10/100 of x= ⅒x

Remaining cows= x-⅒x= 9/10x

2%of remaining cows= 2/100 of 9/10x= 9/500x

A/q

now, 9/10x- 9/500x = 63

so, 441/500x = 63

so, x= 63×500/441= 31500/441

please mark it as brainlist answer.