Question

b.
10. The length of diameter of
base of a hemispherical tomb is 42 dm. Let us write by calculating the
cost of colouring the upper surface of the tomb at the rate of 35 per square metre.
(ii) If
11. Two hollow sphrers with the lengths of diameter 21 cm and 17.5 cm respectively are made​

Answer 1

Answer:

Given:

Diameter of base = 42dm

Formula Used:

1. Diameter of hemisphere = 2×Radius

Radius = 42/2 = 21dm = 2.1m

2. Surface area of hemisphere =

$2 \times \pi \times (2.1)^{2}$

Surface Area =

$2 \times \pi \times (2.1)^{2}$

=27.72 m²

3. Cost of coloring = Surface Area × Cost per sq

Cost of coloring = 27.72 × 35 = Rs 970.2

Answer 2

Answer:

here is your answer

the cost of colouring the upper surface of the tomb at the rate of 35 per square metre is rupees 970.20