(b) (100 + {30-(5 ~ 2)}] x 15
(d) 999 [72 = {65 + (84 = 12)}]
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Answer:
Step-by-step explanation:
aim : 100+{30-(5*2)}]*15 solve bodmas
100+{30-(5*2)}]*15
actuall u missed a bracket
it is
100+[{30-(5*2)}]*15
=> so,
100+[{30-(5*2)}]*15
100+[{30-10}]*15
100 + [20] * 15
100 + 300
400
999× [72÷{65+(84÷12)}]
999×[72÷{65+7)}]
=999×[72÷72]
=999×1
=999 ans
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