Question

b) (2^-1 + 4^-1 + 6^ -1 + 8^-1)^x  = 1 then x=?​

Answer 1

Answer:

answer is x=0

Step-by-step explanation:

$( { {2}^{ - 1} + {4}^{ - 1} + {6}^{ - 1} + {8}^{ - 1} })^{x} = 1 \\ ({ - 2 - 4 - 6 - 8})^{x} = 1 \\ ( { - 6 - 14})^{x} = 1 \\( { - 20})^{x} = 1 \\ ( { - 20})^{0} = 1 \\ so \: \: x = 0$