Question

b) 2 underoot 2 x²+9
x+5 underoot 2
so factorise by spilliting the middle term
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Answer 1

Answer:

=(x + √2)( 2√2x+5)

Step-by-step explanation:

2√2x²+9x+5√2

here   coeffiecient of x²*constant

=2√2*5√2=10*√2√2=20

Thus we can split 9 into 4 and 5

4+5=9 ans 4*5=20

2√2x²+9x+5√2

=2√2x²+4x+5x+5√2

=2√2x ( x+4/2√2) +5 (x+√2)

=2√2x ( x +2/√2 ) +5 (x+√2)

=2√2x ( x +√2) +5( x+√2)

=(x + √2)( 2√2x+5)

Answer 2

Answer:

( x + √2 ) ( 2√2x + 5 )

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