Math, asked by karkisova798, 3 months ago

b)
2 years ago, father's age was nine times the son's age but 3 years later it will be 5 times only.
Find the present ages of father and son.​


JagadishChandraBose: 3:27
5:29 <--- Current Age
8:40

Answers

Answered by Anonymous
2

Given,

2 years ago, father's age was nine times the son's age but 3 years later it will be 5 times only.

To find,

The present ages of father and son.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the present age of father = x years

And, the present age of son = y years

2 years ago,

The age of father = (x-2) years

The age of son = (y-2) years

According to the data mentioned in the question,

(x-2)÷(y-2) = 9

x-2 = 9y-18

x-9y = -16....(1)

And,

3 years later,

The age of father = (x+3) years

The age of son = (y+3) years

According to the data mentioned in the question,

(x+3)÷(y+3) = 5

x+3 = 5y+15

x-5y = 12....(2)

Subtracting (2) from (1) we get that,

x-9y-x+5y = -16-12

-4y = -28

y = 7

Putting the value of y, into equation (2/

x-(5×7) = 12

x-35 = 12

x = 12+35

x = 47

Hence, present age of father is 47 years and present age of son is 7 years.

Answered by pulakmath007
1

SOLUTION

GIVEN

2 years ago, father's age was nine times the son's age but 3 years later it will be 5 times only.

TO DETERMINE

The present ages of father and son.

EVALUATION

Here it is given that 2 years ago, father's age was nine times the son's age

Let 2 years ago son's age was x years

Then father's age = 9x years

So present age of son = (x+2) years and present age of father = (9x+2) years

So after 3 years son's age will be = (x+5) years and father's age will be = (9x+5) years

So by the given condition

9x + 5 = 5( x + 5 )

 \implies \sf{9x + 5 = 5x + 25}

 \implies \sf{4x  = 20}

 \implies \sf{x  = 5}

Hence present age of son = 7 years and present age of father = 47 years

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