b)
2 years ago, father's age was nine times the son's age but 3 years later it will be 5 times only.
Find the present ages of father and son.
Answers
Given,
2 years ago, father's age was nine times the son's age but 3 years later it will be 5 times only.
To find,
The present ages of father and son.
Solution,
We can simply solve this mathematical problem by using the following mathematical process.
Let, the present age of father = x years
And, the present age of son = y years
2 years ago,
The age of father = (x-2) years
The age of son = (y-2) years
According to the data mentioned in the question,
(x-2)÷(y-2) = 9
x-2 = 9y-18
x-9y = -16....(1)
And,
3 years later,
The age of father = (x+3) years
The age of son = (y+3) years
According to the data mentioned in the question,
(x+3)÷(y+3) = 5
x+3 = 5y+15
x-5y = 12....(2)
Subtracting (2) from (1) we get that,
x-9y-x+5y = -16-12
-4y = -28
y = 7
Putting the value of y, into equation (2/
x-(5×7) = 12
x-35 = 12
x = 12+35
x = 47
Hence, present age of father is 47 years and present age of son is 7 years.
SOLUTION
GIVEN
2 years ago, father's age was nine times the son's age but 3 years later it will be 5 times only.
TO DETERMINE
The present ages of father and son.
EVALUATION
Here it is given that 2 years ago, father's age was nine times the son's age
Let 2 years ago son's age was x years
Then father's age = 9x years
So present age of son = (x+2) years and present age of father = (9x+2) years
So after 3 years son's age will be = (x+5) years and father's age will be = (9x+5) years
So by the given condition
9x + 5 = 5( x + 5 )
Hence present age of son = 7 years and present age of father = 47 years
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