Math, asked by ysandeep79, 10 months ago

b/2b-(6+6b)= -2/7 solve the equation

Answers

Answered by VedankMishra
0

Answer:

b in (-oo:+oo)

(b/2)*b-(6*b)-6 = ((-b)^2)/7 // - ((-b)^2)/7

(b/2)*b-(((-b)^2)/7)-(6*b)-6 = 0

(b/2)*b+(-1/7)*b^2-6*b-6 = 0

5/14*b^2-6*b-6 = 0

DELTA = (-6)^2-(-6*5/14*4)

DELTA = 312/7

DELTA > 0

b = ((312/7)^(1/2)+6)/(5/14*2) or b = (6-(312/7)^(1/2))/(5/14*2)

b = 7/5*((312/7)^(1/2)+6) or b = 7/5*(6-(312/7)^(1/2))

b in { 7/5*(6-(312/7)^(1/2)), 7/5*((312/7)^(1/2)+6) }

Answered by rohithreddy2001
2

Answer:

-73/84

Step-by-step explanation:

given b/2b-(6+6b)= -2/7

1/2-(6+6b)=-2/7

6+6b=1/2+2/7

6+6b=11/14

6b=11/14-6

6b=-73/14

b=-73/84

hope it helps

please mark it as brainliest

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