Question

b)2root2a3+8b3-27c3 +18abc​

Answer 1

Answer:

please elaborate ur question

Step-by-step explanation:

2 root 2a...please write correctly

Answer 2

Answer:

$(\sqrt{2}a+2b+(-3c))(2a^{2}+4b^{2} +3c^{2} - (2\sqrt{2}ab - 6bc + 3\sqrt{2}ac)$

Step-by-step explanation:

Identity to be used:- a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac)

2$\sqrt{2}$$a^{3}$+8$b^{3}$-27$c^{3\\}$ +18abc​

=$(\sqrt{2}a)^{3} +(2b)^{3} + (-3c)^{3} - 3(\sqrt{2} a)(2b)(-3c)$

=$(\sqrt{2}a+2b+(-3c))(\sqrt{2}a^{2} + 2b^{2} + (-3c)^{2} - (\sqrt{2}a)(2b) - (2b)(-3c) - (\sqrt{2}a)(-3c)$

=$(\sqrt{2}a+2b+(-3c))(2a^{2}+4b^{2} +3c^{2} - (2\sqrt{2}ab - 6bc + 3\sqrt{2}ac)$

Hope it helps. Please mark as brainliest!