Question

(b) 3.0 g of H, react with 30.0 g of O, yield H2O.
(i) Which is the limiting reagent?
(ii) Calculate the maximum amount of H2O that can be formed
(iii) Calculate the amount of reactant left unreacted.
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Answer 1

Answer:

see the explanation

Explanation:

2H2+O2=2H20

4g+32g=36g

4g H2 react with 32 g O to produce 36 g H20

then 3g H2 react with 24g O to produce 27g H20

since 3g of H2 is completely used in the reaction so Hydrogen is the limiting reactant

27g of H20 formed from the reaction so minimum amount of H20 formed in the reaction is 27g

24g O2 from 30g O2 is used in the reaction

so 6g O2 is left unreacted