B
с
3. AD and BC are equal perpendiculars to a line
segment AB (see Fig. 7.18). Show that CD bisects
AB.
0
D
Answers
Step-by-step explanation:
Step-by-step explanation:From figure,
Step-by-step explanation:From figure,In △OAD & △OBC
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠C
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BC
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BCSo, byASA congruence criterion rule,
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BCSo, byASA congruence criterion rule,△OAD is congruent to △OBC
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BCSo, byASA congruence criterion rule,△OAD is congruent to △OBCTherefore,
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BCSo, byASA congruence criterion rule,△OAD is congruent to △OBCTherefore,OA=OB
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BCSo, byASA congruence criterion rule,△OAD is congruent to △OBCTherefore,OA=OBHence,
Step-by-step explanation:From figure,In △OAD & △OBC∠B=∠A.. .....(90 o )And,∠D=∠CAnd,AD=BCSo, byASA congruence criterion rule,△OAD is congruent to △OBCTherefore,OA=OBHence, CD bisects AB
Question :-
AD and BC are equal perpendiculars to a line segment AB (see figure). Show that CD bisects AB.
Answer :-
In ∆BOC and ∆AOD, we have
∠BOC = ∠AOD
BC = AD [Given]
∠BOC = ∠AOD [Vertically opposite angles]
∴ ∆OBC ≅ ∆OAD [By AAS congruency]
⇒ OB = OA [By C.P.C.T.]
i.e., O is the mid-point of AB.
Thus, CD bisects AB.
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