Question

(b) 3
(c) 4
(d) 5
Which of the following reagents converts alkene into alcohol ?
(a) HOH/H2SO4
(b) (1) BH; (ii) H202/OH
c) () Hg(OAC)2 (in) H202 NaBH4
(d) All of these
12. In this given reaction,​

Answer 1

Answer:

your answer is (b) CORRECT ANSWER

Answer 2

(b) (1) BH; (ii) H202/OH

The addition of borane (BH3) in tetrahydrofuran solvent (THF) to the alkene, followed by the addition of hydrogen peroxide (H2O2) and sodium hydroxide (NaOH), make the anti-Markovnikov alcohol. Hydroboration-oxidation is a two-step pathway used to produce alcohols. The reaction proceeds in an anti-Markovnikov manner, where the hydrogen (from BH3 or BHR2) attaches to the more substituted carbon and the boron attaches to the least substituted carbon in the alkene double bond. Furthermore, the borane acts as a Lewis acid by accepting two electrons in its empty p orbital from an alkene that is electron-rich. This process allows boron to have an electron octet. A very interesting characteristic of this process is that it does not require any activation by a catalyst. The hydroboration mechanism has the elements of both hydrogenation and electrophilic addition and it is stereospecific (syn addition), meaning that the hydroboration takes place on the same face of the double bond, this leads to cis stereochemistry.