b) 3(y + 1) – 2(y + 1) = 5 by transposing method
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3(y+1) - 2(y+1) = 5
3y + 3 -2y - 2 = 5
3y - 2y +3 - 2 = 5
y + 1 = 5
y = 5 - 1
y = 4
3y + 3 -2y - 2 = 5
3y - 2y +3 - 2 = 5
y + 1 = 5
y = 5 - 1
y = 4
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