Question

(b) 3a - 2b + C + 3 and a + 3b - 2c - 4​

Answer 1

$\huge\mathcal\colorbox{blue}{\color{white}{AnSwEr~↓~↓~}}$

$\tt (3a - 2b + c + 3) + (a + 3b - 2c - 4) \\ \tt = (3a + a) + ( - 2b + 3b) + (c - 2c) + (3 - 4) \\ = \color{blue}{ \underline{ \boxed{ \tt4a + b - c - 1}}}$

$\huge\mathtt\color{blue}{Hope~it~helps..!!}$

Answer 2

$\sf3a−2b+c+3anda+3b−2c−4$

$\sf=(3a−2b+c+3)+(a+3b−2c−4)$

$\sf=3a−2b+c+3+a+3b−2c−4$

$\sf=4a+b−c−1$