Question

b) 4.0 d (9, 2H)
b) 7.20 (d, j =
ul. Uit, 3H)
c) 2.2 8 (s, 3H)
x) M.F. = CH N
UV = 235 nm ( € 1500)
NMR = a) 2.4 D (s, 15mm)
c) 7.5 8 (d, j = 8Hz, 10mm)
xi) M.F. = C5H100
IR = 1775 cm, 1240 cm!
PMR = a) 3.4 / S, 6H
c) 4.8 8 S, IH.
xii) M.F = CHEON
UV = 210 nm
IR = 2250 cm, 1750 cm!
b) 3.8 8 3,3
b38 S.
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Answer 1

Answer:

C is the right answer

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