B
4. Draw a line segment AB = 6 cm. Take a point C on AB such that AC = 4 cm. From C, draw
CD I AB
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Step-by-step explanation:
Since tangents to a circle is perpendicular to the radius through the point.
∴∠ORD=∠OSD=90
o
It is given that ∠D=90
o
. Also, OR=OS. Therefore, ORDS is a square.
Since tangents from an exterior point to a circle are equal in length.
∴BP=BQ CQ=CR and, DR=DS.
Now,
BP=BQ
⇒ BQ=27 [∵BP=27 cm (Given)]
⇒BC−CQ=27
⇒38−CQ=27
∵ BC=38cm ⇒CQ=11 cm
⇒CR=11 [∵CR=CQ]
⇒CD−DR=11
⇒25−DR=11 [∵CD=25cm]
⇒DR=14 cm
But, ORDS is a square. ⇒ OR=DR=14 cm.
⇒ r=14 cm.
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