B. 4. In the adjoining figure, all measurements are in metres. Find the perimeter of the quadrilateral ABCD.
60 А
14 D
48 C
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Answer:
Given ∠BAD=90∘,∠BDC=90∘AB=6cmAD=8cmBC=26cm
In right angle △ABD
BD=AB2+AD2=62+82=100=10cm
In right angle △BCD
CD=BC2−BD2=262+102=242=24cm
∴ Area of quadrilateral ABCD
=ar(△ABD)+ar(△BCD)
=21×6×8+21×10×24=3×8+5×24=24+120=144cm2
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