Question

(b)
4. Tillnutes
fiv) 2 minutes
The HCF of two numbers is 11 and their LCM is 7700. If one of the numbers is
275, then the other number is-
(1) 279
(ii) 283
fi) 308
(iv) 318​

Answer 1

Answer:

The other no. is iii) 308

Step-by-step explanation:

Let the other no . be x

1 st number = 275

HCF = 11

LCM = 7700

We know that ,

LCM × HCF = Product of two numbers

∴ 7700 × 11 = 275 × $x$

⇒ 84700 = 275 × $x$

⇒ $x = \frac{84700}{275}$

⇒ $x =$ 308

I hope it helps u dear friend