Question

b)5+√3/5-√3= a + 3b√15​

Answer 1

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its just like your question on this basis you sol it ok Given (√3-1) / (√3 + 1) (rationalize numarator and denominator(√3

1))

→ (√3-1)(√3 - 1) / (√3 + 1)(√3 - 1)

→ (√3 - 1)2 / (3-1)

⇒ (3 + 1-2√3)/2

⇒ (2-√3)= a+b√3 ⇒a= 2 and b = -1

Sol2):

Given (√2+√3)(3- √2-2-

(3-√2 + 2√3))

√3) (rationalize numarator and denominator

→ (√2+√3)(3-√2+2√3)/(3√2-2√3)(3√2+2√3)

⇒ (12+5/6) / (18-12)

→ (2+ (5/6) /6 ) = a-b√6

a = 2 and b = -5/6.

Plz MARK AS BRAINLIEST

Answer 2

Answer:

5+root 3/5-root 3 =a+3b root 15

=5+root 3 / 5-root 3 × 5+root 3 / 5+ root 3 = a+3b root 15

= (5+root 3)square /(5)^2 +(root) ^2=a+3b root 15

= (5)^2 + (root 3) ^2 +2× 5×root 3/ 25-3 =a+3b root 15

= 25 + 3 + 10 root 3 /21 = a+3b root 15

= 28+10 root 3/21 =a+ 3b root 15

a= 28/21

=4/3

3b root 15= 10 root 3

=10 root 3/ 3 root 15

= 10/3 root 5