Physics, asked by Anonymous, 9 months ago

(b) 5 ms
(C) yg ms
(0)3 6 m/s
4.
Avertical spring of force constant 100 N/m is attached with a hanging mass of 10 kg Now an external force
is applied on the mass so that the spring is stretched by additional 2m. The work done by the force Fis
(g = 10 m/s)
* = 100M
10kg
(A) 2003
(8) 400 J
(C) 450 J
(D) 600 J

very urgent ​Plzzz frnd try itt please

Answers

Answered by era45
2

Explanation:

listen here displacement is 2m intial it was on equilibrium state.hope u get it

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