Math, asked by jagdishthakkar310, 9 months ago

b. 5a^5 - 4a^3 + 6a^2 - 8a + 16 divide by 4a^2​

Answers

Answered by revathi15abi
0

Step-by-step explanation:

(5a^5 - 4a^3 + 6a^2 - 8a + 16) /(4a^2)

= (5(a^3)/4 - a+ 3/2 - 2(a^(-1) + 4(a^(-2) )

Similar questions