Question

B 6. In the figure, O is the centre of the circle. If I (AC) = 33, I (CB) = 44. then I (CO) = ? (1) 55 (2) 27.5 (3) 22 (4) 16.5 = A ​

Answer 1

Answer:

Hi Mate,

Since AB is straight line therefore by theorum < ACB is 90°.

So, ∆ABC is a right triangle.

Pythagoras theorum

H² = B² + P²

AB² = AC² + BC²

AB² = 33² + 44²

AB = √( 1089 + 1936 )

AB = 55 cm.

Since AB is a diameter then,

AB = 2AO

55 cm = 2 × AO

27.5 cm = AO

Since, AO = CO = BO = radius.

Hence CO is 27.5 cm.

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