Math, asked by ramcharan90, 7 months ago

b) 72
c) 73
If d(N) represents number of divisors of N then d(d(18)) is
a)
72
ERALD PACKAGE
a) 4
b) 5
c) 6
The product of divisors of 512 is
a) 245
b) 254
c) 2100
c) 3
The number of prime factors of 54 is
a) 8
b) 2
The product of divisors of N is
Id(N)
a)
N
b) N(N)
c) N
wan​

Answers

Answered by sharonmajelakpt2020
0

Answer:

Step-by-step explanation:

d(18) = number of divisors of 18

The of divisors are 1, 2, 3, 6, 9, 18

Therefore, Number of divisors of 18 = 6

Therefore, d(18)=6 --------------(1)

Now,

As we have to fine d(d(18))

From result 1 we substitute d(18)=6 in d(d(18))

therefore, Now we have to find d(d(18)) = d(6)

the divisors of 6 = 1, 2, 3, 6

therefore d(6) = 4

Answer:- d(d(18)) = 4

Answered by Navya3072008
0

Answer:

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