Question

B
8. Find the area of an isosceles triangle whose perimeter is 32cm and its base is 12cm.​

Answer 1

Answer:

ans= 96 cm^2

Step-by-step explanation:

perimeter of triangle= a+b+c

in isosceles two sides are equal of we can say

a=b

so,

a+b+c=a+a+b

a+a+c=32cm

=2a+12=32

=2a=32-12

=a=20/2

=a=10cm =b

area of trianlge = under root(s[s-a]*[s-b]*[s-c])

s= perimeter/2

=32/2

=16cm

= under root (16[16-10]*[16-10]*16-12])

=under root (16*6*6*4)

=9*3*2*2

area =96cm^2

hope you got it

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