b. 85 x 15
2. In a cricket tournament, Team A scored 30 sixes and 35 fours, while Team B scored 22
sixes and 47 fours. Which team scored maximum runs?
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Answer:
First let's count the total runs of team A and B.
Runs scored by team A = ( 30 × 6 ) + ( 35 × 4 ) = (180)+(140) = 320 runs
Runs scored by team B = ( 22 × 6 ) + ( 47 × 4 ) = (132)+(188) = 320runs
Therefore Runs scored by team A = Runs scored by team B
320 runs = 320 runs
Therefore Both the team's scored equal runs i.e 320 runs.
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